mobile software developer, milano
 Work Experience
full stack developer milano Currently i'm working as mobile developer for the Mobile (iOS/Android) App (download here), of an innovative crowdsourcing company named BeMyEye located in Milan (IT).



mobile developer milano In the past i've worked as software developer (also mobile) in Cutaway SRL (Milan - IT) from 2007 to 2014, located to SEAT Pagine Gialle (Milan - IT) as iOS Developer consultant.



In spare time, i'm a student in "Sicurezza dei Sistemi e delle Reti Informatiche" in Milan.

Parallel to work, i try to make something useful, like robots, apps, games and innovative startups.

I'm co-founder of Youcius and 10meters startups.
software mobile developer app
 Expertize

objective-c

 

swift

 

C

 

C++

 

nodeJS

 

angularJS

 

git

 

svn

 

xml

 

json

 

python

 

shell

 

java

 

android

 

C#

 

javascript

 

php4

 

php5

 

mySQL

 

mongoDB

 

read more on Linkedin profile, StackOverflow Q&A, Github repository.
senior ios developer milano
 Awards

2015 - Awarded for entering the top 5% of C++, the top 10% Objective-C and the top 20% of Node.js coders on CodeEval.com by implementing algorithms and solution to problems in the C++/Objective-C/Node.js languages.

2014 - Winner of the Milano BluHackathon. Purpose of this hackathon is to make in a day, an iOS and Android app, to keep up to date and to informs citizens about the public water of Milan.

2012 - The Last Two, game for Windows Phone 7, was selected for the Nokia App Highlight.

latest tutorials[] || snippets[] from whileTrue(){} blog.

software developer milano, mobile app developer milano, full stack

Interested for something?

Drop me an email. Build and run!
Just for fun, of course ...and anti spam!

#include
#define kBirthdate 2810
int N(int n, int k) {
  if (n == 0) return k == 0 ? 1 : 0;
  return (N(n-1, k-1) + N(n-1, k)*(n-1-k)) + N(n-1, k+1)*(k+1) % kBirthdate;
}
int main(int argc, const char * argv[]) {
  int num[] = {N(3,6)+105,N(8,5)-2,102,N(8,5)-1,64,97+N(3,6),
    108,98,101,N(8,5)+2,116,N(8,5)-1,N(8,5),
    97,115,99,97,(N(8,6)*2)-10,105,N(8,5)+4};

  for ( auto n : num ) printf ( "%c", n );
  printf("\n");
  return 0;
}