Alberto Pasca - software developer | mobile

Work Experience

[2017-current]
Software developer / iOS for Pirelli (Milan - IT) in the Data Science and Analytics team, as part of the Pirelli Connesso project (http://pirelliconnesso.com/).

Company info: Pirelli Tyre, Milan - IT.

[2014-2017]
Software developer / iOS first worked on the new native app (iOS/Android) and next as fullstack developer.

Company info: BeMyEye, Milan - IT.

[2007-2014]
ICT Consultant as software developer / iOS in Cutaway SRL, located to SEAT Pagine Gialle (now ItaliaOnLine) (Milan - IT).

Company info: Cutaway, Milan - IT.

Company info: ItaliaOnLine, Milan - IT.

software developer, mobile (iOS/Android)

Mobile apps

Some of the major projects, availables on the stores. Others on github or to Enterprise store.

Expertize

swift

objective-c

kotlin

android

C++

nodeJS

angularJS

git

svn

xml

json

python

shell

java

javascript

php4

php5

mySQL

mongoDB

read more on Linkedin profile, StackOverflow Q&A, Github repository.

Awards

2015 - Awarded for entering the top 5% of C++, the top 10% Objective-C and the top 20% of Node.js coders on CodeEval.com by implementing algorithms and solution to problems in the C++/Objective-C/Node.js languages.

2014 - Winner of the Milano BluHackathon. Purpose of this hackathon is to make in a day, an iOS and Android app, to keep up to date and to informs citizens about the public water of Milan.

2012 - The Last Two, game for Windows Phone 7, was selected for the Nokia App Highlight.

latest tutorials[] || snippets[] from whileTrue(){} blog.

software developer milano, mobile app developer milano, full stack

Interested for something?

Drop me an email. Build and run!
Just for fun, of course ...and anti spam!

#include
#define kBirthdate 2810
int N(int n, int k) {
  if (n == 0) return k == 0 ? 1 : 0;
  return (N(n-1, k-1) + N(n-1, k)*(n-1-k)) + N(n-1, k+1)*(k+1) % kBirthdate;
}
int main(int argc, const char * argv[]) {
  int num[] = {N(3,6)+105,N(8,5)-2,102,N(8,5)-1,64,97+N(3,6),
    108,98,101,N(8,5)+2,116,N(8,5)-1,N(8,5),
    97,115,99,97,(N(8,6)*2)-10,105,N(8,5)+4};

  for ( auto n : num ) printf ( "%c", n );
  printf("\n");
  return 0;
}